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DT WK_OF_YR 7 select dt, to_number(to_char(dt, 'iw')) wk_of_yr Let's look at both of them and see what differences they contain and how they can throw the listed assumptions 'out of the window'. 10 select dt, wk_of_yr A long while back someone asked the following question, which seems simple enough: That same question popped up just recently so I dug out the example I made in2009 which is still relevant today. 8 from date_wk 7 select dt, to_number(to_char(dt, 'iw')) wk_of_yr You can unsubscribe at any time. DT WK_OF_YR The Oracle documentation contains a complete SQL reference. 04-JAN-10 1 4 connect by level <= 366 8 from date_wk By signing up you agree to our Terms of Use and Privacy Policy. Thanks. SQL> Select TRUNC(sysdate, ‘IW’) FROM_DATE, 2 NEXT_DAY(TRUNC(sysdate+50,’IW’),’SUNDAY’) TO_DATE from dual; FROM_DATE TO_DATE——— ———23-JUN-03 17-AUG-03. Latest Tech Product Launches in AI, Big Data, Cloud and More: Week of June 18, 2020, Load Hard-Coded “NULL” Keyword in a Target Column, Top 5 Programmatic Advertising Platforms for 2020 and Beyond, How to Overcome Hiring Bias to Tap Hidden Talent, Elon Musk Rolls Out Tesla’s Full Self-Driving Beta, Experts Sound Caution, Remote First: Creating Resilient Organizations, What Is an Inclusive Workplace? In such a system February 8, 2009, would be the starting date for Week 7 (because Week 1 only has three days, January 1,2 and 3, a strange occurrence indeed as it contradicts the stated definition of every week starting on a Sunday). 4 connect by level <= 366 2 select to_date('01/01/'||to_char(sysdate, 'RRRR'), 'MM/DD/RRRR') + rownum - 1 dt 5 ), 11 from wk_dt 10 select min(dt) 6 wk_dt as ( 3 from dual Such assumptions depend upon which week numbering 'scheme' one elects to use, and there are two common schemes currently in use by Oracle. 11 from wk_dt Is this answer out of date? 11 from wk_dt SQL> 5 ), 6 wk_dt as ( Thanks for the question, Silvana. 8 from date_wk First Date of Week(Monday Date) Using PO_DT field in Oracle, Trying to get the First Date of week based on value of PO_DT. MIN(DT) The modulo (MOD) expression returns 0 if today is Saturday, 1 if it is Sunday, etc. Explanation. 16-FEB-09 7 WeekDay ( ) 4. 11 from wk_dt Function . 14-FEB-09 7 13 / 11 from wk_dt iw is nothing but international week starts on Monday. 7 select dt, to_number(to_char(dt, 'iw')) wk_of_yr 09-FEB-09 7 They ARE different in how they define Week number 1 and that can throw a 'monkey wrench' into any methodology one could implement to answer the above listed question. If 1 January is on a Friday, Saturday or Sunday, it is in week 52 or 53 of the previous year. If we use the U.S week numbering system we can easily satisfy the first condition listed in the posted question as Week 2 is defined as the week containing January 1: [In Oracle syntax the format specifier for the U.S. week numbering system is WW, in either upper or lower case. © 1995-2020 Toolbox is among the trademarks of. 3 from dual Result. 2 select to_date('01/01/2010', 'MM/DD/RRRR') + rownum - 1 dt Try This….this is in Sql server 2000……..————-, declare @d datetimedeclare @numbers table (n int), insert into @numbers(n)select 0 union allselect 1 union allselect 2 union allselect 3 union allselect 4 union allselect 5 union allselect 6 union allselect -1 union allselect -2 union allselect -3 union allselect -4 union allselect -5 union allselect -6, select min(d) AS WeekBegin, max(d) AS WeekEndfrom( select dateadd(d, n, @d) as d, datepart(week, dateadd(d, n, @d)) as w from @numbers) twhere datepart(week, @d) = w. SELECT DECODE (trim(TO_CHAR (in_date), ‘day’)), ‘monday’, in_date)+0, ‘tuesday’, in_date) – 1, ‘wednesday’, in_date) – 2, ‘thursday’, in_date) – 3, ‘friday’, in_date) – 4, ‘saturday’,in_date)-5, ‘sunday’,in_date)-6 ) start_day, DECODE (trim(TO_CHAR (in_date), ‘day’)), ‘monday’, in_date)+5, ‘tuesday’, in_date) + 4, ‘wednesday’, in_date) + 3, ‘thursday’, in_date) + 2, ‘friday’, in_date) + 1, ‘saturday’,in_date)+0, ‘sunday’,in_date)+6 ) end_day FROM DUAL. 2 select to_date('01/01/2010', 'MM/DD/RRRR') + rownum - 1 dt 13 / 11 from wk_dt 10-FEB-09 7 5 ), Answered by: Sergiusz Wolicki - Last updated: March 19, 2018 - 8:12 pm UTC.

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